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									【程序91】
 题目:时间函数举例1
 1.程序分析:
 2.程序源代码:
 #include "stdio.h"
 #include "time.h"
 void main()
 { time_t lt; /*define a longint time varible*/
 lt=time(NULL);/*system time and date*/
 printf(ctime()); /*english format output*/
 printf(asctime(localtime()));/*tranfer to tm*/
 printf(asctime(gmtime())); /*tranfer to Greenwich time*/
 }
 ==============================================================
 【程序92】
 题目:时间函数举例2
 1.程序分析:
 2.程序源代码:
 /*calculate time*/
 #include "time.h"
 #include "stdio.h"
 main()
 { time_t start,end;
 int i;
 start=time(NULL);
 for(i=0;i3000;i++)
 { printf("1111111111n");}
 end=time(NULL);
 printf("1: The different is %6.3fn",difftime(end,start));
 }
 ==============================================================
 【程序93】
 题目:时间函数举例3
 1.程序分析:
 2.程序源代码:
 /*calculate time*/
 #include "time.h"
 #include "stdio.h"
 main()
 { clock_t start,end;
 int i;
 double var;
 start=clock();
 for(i=0;i10000;i++)
 { printf("1111111111n");}
 end=clock();
 printf("1: The different is %6.3fn",(double)(end-start));
 }
 ==============================================================
 【程序94】
 题目:时间函数举例4,一个猜数游戏,判断一个人反应快慢。(版主初学时编的)
 1.程序分析:
 2.程序源代码:
 #include "time.h"
 #include "stdlib.h"
 #include "stdio.h"
 main()
 {char c;
 clock_t start,end;
 time_t a,b;
 double var;
 int i,guess;
 srand(time(NULL));
 printf("do you want to play it.('y' or 'n') n");
 loop:
 while((c=getchar())=='y')
 {
 i=rand()%100;
 printf("nplease input number you guess:n");
 start=clock();
 a=time(NULL);
 scanf("%d",&guess);
 while(guess!=i)
 {if(guessi)
 {printf("please input a little smaller.n");
 scanf("%d",&guess);}
 else
 {printf("please input a little bigger.n");
 scanf("%d",&guess);}
 }
 end=clock();
 b=time(NULL);
 printf("1: It took you %6.3f secondsn",var=(double)(end-start)/18.2);
 printf("1: it took you %6.3f secondsnn",difftime(b,a));
 if(var15)
 printf("11 You are very clever! 11nn");
 else if(var25)
 printf("11 you are normal! 11nn");
 else
 printf("11 you are stupid! 11nn");
 printf("11 Congradulations 11nn");
 printf("The number you guess is %d",i);
 }
 printf("ndo you want to try it again?("yy".or."n")n");
 if((c=getch())=='y')
 goto loop;
 }
 ==============================================================
 【程序95】
 题目:家庭财务管理小程序
 1.程序分析:
 2.程序源代码:
 /*money management system*/
 #include "stdio.h"
 #include "dos.h"
 main()
 {
 FILE *fp;
 struct date d;
 float sum,chm=0.0;
 int len,i,j=0;
 int c;
 char ch[4]="",ch1[16]="",chtime[12]="",chshop[16],chmoney[8];
 pp: clrscr();
 sum=0.0;
 gotoxy(1,1);printf("|---------------------------------------------------------------------------|");
 gotoxy(1,2);printf("| money management system(C1.0) 2000.03 |");
 gotoxy(1,3);printf("|---------------------------------------------------------------------------|");
 gotoxy(1,4);printf("| -- money records -- | -- today cost list -- |");
 gotoxy(1,5);printf("| ------------------------ |-------------------------------------|");
 gotoxy(1,6);printf("| date: -------------- | |");
 gotoxy(1,7);printf("| | | | |");
 gotoxy(1,8);printf("| -------------- | |");
 gotoxy(1,9);printf("| thgs: ------------------ | |");
 gotoxy(1,10);printf("| | | | |");
 gotoxy(1,11);printf("| ------------------ | |");
 gotoxy(1,12);printf("| cost: ---------- | |");
 gotoxy(1,13);printf("| | | | |");
 gotoxy(1,14);printf("| ---------- | |");
 gotoxy(1,15);printf("| | |");
 gotoxy(1,16);printf("| | |");
 gotoxy(1,17);printf("| | |");
 gotoxy(1,18);printf("| | |");
 gotoxy(1,19);printf("| | |");
 gotoxy(1,20);printf("| | |");
 gotoxy(1,21);printf("| | |");
 gotoxy(1,22);printf("| | |");
 gotoxy(1,23);printf("|---------------------------------------------------------------------------|");
 i=0;
 getdate(&d);
 sprintf(chtime,"%4d.%02d.%02d",d.da_year,d.da_mon,d.da_day);
 for(;;)
 {
 gotoxy(3,24);printf(" Tab __browse cost list Esc __quit");
 gotoxy(13,10);printf(" ");
 gotoxy(13,13);printf(" ");
 gotoxy(13,7);printf("%s",chtime);
 j=18;
 ch[0]=getch();
 if(ch[0]==27)
 break;
 strcpy(chshop,"");
 strcpy(chmoney,"");
 if(ch[0]==9)
 {
 mm:i=0;
 fp=fopen("home.dat","r+");
 gotoxy(3,24);printf(" ");
 gotoxy(6,4);printf(" list records ");
 gotoxy(1,5);printf("|-------------------------------------|");
 gotoxy(41,4);printf(" ");
 gotoxy(41,5);printf(" |");
 while(fscanf(fp,"%10s%14s%fn",chtime,chshop,&chm)!=EOF)
 { if(i==36)
 { getch();
 i=0;}
 if ((i%36)17)
 { gotoxy(4,6+i);
 printf(" ");
 gotoxy(4,6+i);}
 else
 if((i%36)16)
 { gotoxy(41,4+i-17);
 printf(" ");
 gotoxy(42,4+i-17);}
 i++;
 sum=sum+chm;
 printf("%10s %-14s %6.1fn",chtime,chshop,chm);}
 gotoxy(1,23);printf("|---------------------------------------------------------------------------|");
 gotoxy(1,24);printf("| |");
 gotoxy(1,25);printf("|---------------------------------------------------------------------------|");
 gotoxy(10,24);printf("total is %8.1f$",sum);
 fclose(fp);
 gotoxy(49,24);printf("press any key to.....");getch();goto pp;
 }
 else
 {
 while(ch[0]!='r')
 { if(j10)
 { strncat(chtime,ch,1);
 j++;}
 if(ch[0]==8)
 {
 len=strlen(chtime)-1;
 if(j15)
 { len=len+1; j=11;}
 strcpy(ch1,"");
 j=j-2;
 strncat(ch1,chtime,len);
 strcpy(chtime,"");
 strncat(chtime,ch1,len-1);
 gotoxy(13,7);printf(" ");}
 gotoxy(13,7);printf("%s",chtime);ch[0]=getch();
 if(ch[0]==9)
 goto mm;
 if(ch[0]==27)
 exit(1);
 }
 gotoxy(3,24);printf(" ");
 gotoxy(13,10);
 j=0;
 ch[0]=getch();
 while(ch[0]!='r')
 { if (j14)
 { strncat(chshop,ch,1);
 j++;}
 if(ch[0]==8)
 { len=strlen(chshop)-1;
 strcpy(ch1,"");
 j=j-2;
 strncat(ch1,chshop,len);
 strcpy(chshop,"");
 strncat(chshop,ch1,len-1);
 gotoxy(13,10);printf(" ");}
 gotoxy(13,10);printf("%s",chshop);ch[0]=getch();}
 gotoxy(13,13);
 j=0;
 ch[0]=getch();
 while(ch[0]!='r')
 { if (j6)
 { strncat(chmoney,ch,1);
 j++;}
 if(ch[0]==8)
 { len=strlen(chmoney)-1;
 strcpy(ch1,"");
 j=j-2;
 strncat(ch1,chmoney,len);
 strcpy(chmoney,"");
 strncat(chmoney,ch1,len-1);
 gotoxy(13,13);printf(" ");}
 gotoxy(13,13);printf("%s",chmoney);ch[0]=getch();}
 if((strlen(chshop)==0)||(strlen(chmoney)==0))
 continue;
 if((fp=fopen("home.dat","a+"))!=NULL);
 fprintf(fp,"%10s%14s%6s",chtime,chshop,chmoney);
 fputc('n',fp);
 fclose(fp);
 i++;
 gotoxy(41,5+i);
 printf("%10s %-14s %-6s",chtime,chshop,chmoney);
 }}}
 ==============================================================
 【程序96】
 题目:计算字符串中子串出现的次数
 1.程序分析:
 2.程序源代码:
 #include "string.h"
 #include "stdio.h"
 main()
 { char str1[20],str2[20],*p1,*p2;
 int sum=0;
 printf("please input two stringsn");
 scanf("%s%s",str1,str2);
 p1=str1;p2=str2;
 while(*p1!=' ')
 {
 if(*p1==*p2)
 {while(*p1==*p2&&*p2!=' ')
 {p1++;
 p2++;}
 }
 else
 p1++;
 if(*p2==' ')
 sum++;
 p2=str2;
 }
 printf("%d",sum);
 getch();}
 ==============================================================
 【程序97】
 题目:从键盘输入一些字符,逐个把它们送到磁盘上去,直到输入一个#为止。
 1.程序分析:
 2.程序源代码:
 #include "stdio.h"
 main()
 { FILE *fp;
 char ch,filename[10];
 scanf("%s",filename);
 if((fp=fopen(filename,"w"))==NULL)
 {printf("cannot open filen");
 exit(0);}
 ch=getchar();
 ch=getchar();
 while(ch!='#')
 {fputc(ch,fp);putchar(ch);
 ch=getchar();
 }
 fclose(fp);
 }
 ==============================================================
 【程序98】
 题目:从键盘输入一个字符串,将小写字母全部转换成大写字母,然后输出到一个磁盘文件“test”中保存。
 输入的字符串以!结束。
 1.程序分析:
 2.程序源代码:
 #include "stdio.h"
 main()
 {FILE *fp;
 char str[100],filename[10];
 int i=0;
 if((fp=fopen("test","w"))==NULL)
 { printf("cannot open the filen");
 exit(0);}
 printf("please input a string:n");
 gets(str);
 while(str!='!')
 { if(str='a'&&str='z')
 str=str-32;
 fputc(str,fp);
 i++;}
 fclose(fp);
 fp=fopen("test","r");
 fgets(str,strlen(str)+1,fp);
 printf("%sn",str);
 fclose(fp);
 }
 ==============================================================
 【程序99】
 题目:有两个磁盘文件A和B,各存放一行字母,要求把这两个文件中的信息合并(按字母顺序排列),
 输出到一个新文件C中。
 1.程序分析:
 2.程序源代码:
 #include "stdio.h"
 main()
 { FILE *fp;
 int i,j,n,ni;
 char c[160],t,ch;
 if((fp=fopen("A","r"))==NULL)
 {printf("file A cannot be openedn");
 exit(0);}
 printf("n A contents are :n");
 for(i=0;(ch=fgetc(fp))!=EOF;i++)
 {c=ch;
 putchar(c);
 }
 fclose(fp);
 ni=i;
 if((fp=fopen("B","r"))==NULL)
 {printf("file B cannot be openedn");
 exit(0);}
 printf("n B contents are :n");
 for(i=0;(ch=fgetc(fp))!=EOF;i++)
 {c=ch;
 putchar(c);
 }
 fclose(fp);
 n=i;
 for(i=0;in;i++)
 for(j=i+1;jn;j++)
 if(cc[j])
 {t=c;c=c[j];c[j]=t;}
 printf("n C file is:n");
 fp=fopen("C","w");
 for(i=0;in;i++)
 { putc(c,fp);
 putchar(c);
 }
 fclose(fp);
 }
 ==============================================================
 【程序100】
 题目:有五个学生,每个学生有3门课的成绩,从键盘输入以上数据(包括学生号,姓名,三门课成绩),计算出
 平均成绩,况原有的数据和计算出的平均分数存放在磁盘文件"stud"中。
 1.程序分析:
 2.程序源代码:
 #include "stdio.h"
 struct student
 { char num[6];
 char name[8];
 int score[3];
 float avr;
 } stu[5];
 main()
 {int i,j,sum;
 FILE *fp;
 /*input*/
 for(i=0;i5;i++)
 { printf("n please input No. %d score:n",i);
 printf("stuNo:");
 scanf("%s",stu.num);
 printf("name:");
 scanf("%s",stu.name);
 sum=0;
 for(j=0;j3;j++)
 { printf("score %d.",j+1);
 scanf("%d",&stu.score[j]);
 sum+=stu.score[j];
 }
 stu.avr=sum/3.0;
 }
 fp=fopen("stud","w");
 for(i=0;i5;i++)
 if(fwrite(&stu,sizeof(struct student),1,fp)!=1)
 printf("file write errorn");
 fclose(fp);
 }
 
 楼主 2016-10-13 15:05 回复 
 
 
   
             
                  
                  
 
 
 
     
	 
  
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